Re: ||| VuHelp4U ||| Hum Logical adress sy physical address kaisy calculate ker sakty hy

brother complete question send karo zara.

On Fri, Jun 8, 2012 at 9:39 PM, Raazi <mc100401317@vu.edu.pk> wrote:

is ko bhi plz explain ker dain

In the 8086/8088 microprocessor, the physical address is 16 times the selected segment register plus the logical address. For instance, if DS contains 0x1234 and the logical (or effective) address is 0x5678, then the physical address is 0x12340 + 0x5678, which is equal to 0x179B8. 

The calculation of the segment base is left shifting the segment register by 4, which is the same as multiplying it by 16. In all probability, its not even a left shift - its might just be a hardwired offset by 4 bits into a 20 bit adder, but that is an implementation detail that does not need to be considered.

Read more: http://wiki.answers.com/Q/How_you_calculate_the_physical_address_if_i_have_the_logical_address#ixzz1xDjiXGLB 

or  ager  humary pass 

IP=0B10h

Cs=D000h

  ho tu physical addres  kaisy   maloom  kary gy

Or Register kon sa  use hoo ga CS  ya DS

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